编程go协程交叉顺序打印数组

参考解析

题目来源：字节

答案：

使用channel实现交叉打印0-100中的奇偶数。代码如下：

package main
import (
    "fmt"
    "sync"
)
var (
    toOdd  = make(chan struct{})
    toEven = make(chan struct{})
    wg     = sync.WaitGroup{}
)
func main() {
    wg.Add(2)
    go printOdd()
    go printEven()
    wg.Wait()
    fmt.Println("-----done-----")
}
func printOdd() {
    defer wg.Done()
    for i := 1; i <= 100; i += 2 {
        if i != 1 {
            <-toOdd
        }
        fmt.Println(i)
        toEven <- struct{}{}
    }
}
func printEven() {
    defer wg.Done()
    for i := 2; i <= 100; i += 2 {
        <-toEven
        fmt.Println(i)
        if i != 100 {
            toOdd <- struct{}{}
        }
    }
}